继续挑战
第14题地址italy.html
- 网页标题是
walk around，题目内容是一个小图案
，源码中有一行隐藏信息：
<!– remember: 100*100 = (100+99+99+98) + (… –>
按照提示，题目应该是跟小图案和隐藏信息有关，先把图案搞下来：
from io import BytesIO
import requests
from PIL import Image
with requests.Session() as sess:
sess.auth = ('huge', 'file')
response = sess.get('http://www.pythonchallenge.com/pc/return/wire.png').content
img = Image.open(BytesIO(response))
print(img)
<PIL.PngImagePlugin.PngImageFile image mode=RGB size=10000x1 at 0x7F249FC731D0>
我们可以看到，这个小图案的大小是10000x1。
将隐藏信息进行剖析，可以得出，式子是将这10000个像素分成若干组数字的加和。
再结合标题walk around和螺旋形的面包图片联想，这(100+99+99+98)正好是100*100图像的最外圈的像素总和。
题目的意思是让我们将这10000个像素按螺旋形从外到内填充成一张100*100的图像！
不多说，直接开始写算法（假设以左上角开始，顺时针方向，其他方向只是这个结果的旋转和翻转而已）：
from enum import Enum, auto
class Direction(Enum):
Left = auto()
Right = auto()
Up = auto()
Down = auto()
limits = {Direction.Left: 0, Direction.Right: 99, Direction.Up: 0, Direction.Down: 99}
x, y = 0, 0
direction = Direction.Right
img_new = Image.new(img.mode, (100, 100))
img_new_data = img_new.load()
for pixel in img.getdata():
img_new_data[x, y] = pixel
if direction == Direction.Left:
if x <= limits[direction]:
y -= 1
limits[Direction.Down] = y
direction = Direction.Up
else:
x -= 1
elif direction == Direction.Right:
if x >= limits[direction]:
y += 1
limits[Direction.Up] = y
direction = Direction.Down
else:
x += 1
elif direction == Direction.Up:
if y <= limits[direction]:
x += 1
limits[Direction.Left] = x
direction = Direction.Right
else:
y -= 1
elif direction == Direction.Down:
if y >= limits[direction]:
x -= 1
limits[Direction.Right] = x
direction = Direction.Left
else:
y += 1
img_new
结果是一只猫？将地址改为cat.html得到：
and its name is uzi. you’ll hear from him later.
再改为uzi.html，来到了下一题。